A Luchow is categorized under Family Practice Doctors in Tenafly, New Jersey .
| Business Name: | A Luchow |
| Contact Person: | Anya Luchow Liberman |
| Address: | 111 East Clinton Avenue, Tenafly, NJ 07670 |
| Phone Number: | (201) 569-4585 |
A Luchow has been offering Family Practice Doctors from its single location in New Jersey since their foundation in 2010. This company is registered under the SIC code 8011 and NAICS code 621111, which can be used to gain more understanding on the nature of its business.
It now employs 1 to 4 personnel and its B2C services by Family Practice Doctors in the greater New Jersey area contribute to the company’s annual revenue of $100.000 to $499.999. Visit the single location of A Luchow at the coordinates 40.920325,-73.958737, or at their street address of 111 East Clinton Avenue in NJ 07670, United States.
To speak to a representative, call (201) 569-4585 and address inquiries to Anya Luchow Liberman. Alternatively, this business can also be followed and interacted with through the social media platforms Twitter and Facebook . A Luchow’s website can be found at .
| Annual Revenue ($): | $100.000 to $499.999 |
| Location Type: | Single Location |
| Employee #: | 1 to 4 |
| Business Type: | B2C (Business to Consumer) |
| Categorized In: | Family Practice Doctors |
| SIC Code: | 8011 |
| NAICS Code: | 621111 |
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